Question

1. Find the nature of the roots of the following quadratic equations. If the real roots exist,
find them:
(i) 3x² - 3x²+ 5 = 0
(i) 3x²-4√3x+4=0
(iii) 2x²-6x+3=0
​

Answer 1

Answer:

2x2 – 6x + 3 = 0

Here, a = 2, b = -6, c = 3

b2 – 4ac = (-6)2 – 4(2)(3) = 36 – 24 = 12

∴ b2 – 4ac = 12 > 0.

∴ It has two distinct roots. 2x2 – 6x + 3 = 0

Here, a = 2, b = -3, c = 3