Question

1. Find the nth term of the AP-
1 1 1
1.2' 2.3' 3.4
The nth term of​

Answer 1

Answer:

The nth tern of A.P=an_n=1.23-0.399nan

n

=1.23−0.399n

Step-by-step explanation:

Given A.P

1/1.2,1/2.3,1/3.4

a=a_1=\frac{1}{1.2}a=a

1

=

1.2

1

a_2=\frac{1}{2.3}a

2

=

2.3

1

A.P: When the difference between two consecutive terms is constant then, the sequence is called A.P

d=a_2-a_1=\frac{1}{2.3}-\frac{1}{1.2}=-0.399d=a

2

−a

1

=

2.3

1

−

1.2

1

=−0.399

a_n=a+(n-1)da

n

=a+(n−1)d

Substitute the values then we get

a_n=\frac{1}{1.2}+(n-1)(-0.399)=\frac{1.2}-0.399n+0.399=1.23-0.399na

n

=

1.2

1

+(n−1)(−0.399)=

−

1.2

0.399n+0.399=1.23−0.399n

Therefore,nth tern of A.P=an_n=1.23-0.399nan

n

=1.23−0.399n