1. Find the number of atoms in 48 g of ozone at NTP,
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Answer:
(m)Given Mass: 48g of O₃
(M.M)Molecular mass of ozone = 48g.
∵ n=m/M.M
» n=48g/48g=1
∴ n=1 mol
But, as 1 mol. =6.022×10²³ units
∴ 48 g of O₃ contains 6.022×10²³ atoms
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