Chemistry, asked by Incognito444, 9 months ago

1. Find the number of molecules present in 400 gram of NaOH ?
2. 400 gram of NaOH = ______ moles.
3. Mass of 1 molecule of NaOH.

4. Mass of 5 molecules of Na0H.

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Answers

Answered by Anonymous
0

Answer:

Use the molecular formula to find the molar mass; to obtain the number of moles, divide the mass of compound by the molar mass of the compound expressed in grams.

Explanation:

Answered by ankurankur17978
0

Answer

1.The molecular weight of NaOH is 40 g/mol.

30 g of NaOH corresponds to 4030=0.75moles.

0.75 moles of NaOH contains 0.75 moles of Na.

The atomic mass of Na is 23 g/mol.

0.75 moles of Na corresponds to 23×0.75=17 g of Na.

2.What would you like to ask?

Chemistry

Some Basic Concepts of Chemistry

Stoichiometry and Stoichiometric Calculations

10g of NaOH required cert...

CHEMISTRY

Asked on December 30, 2019 byVanshika Sunil

10g of NaOH required certain amount of H2SO4 for complete neutralisation. Calculate the number of atoms of hydrogen, sulphur and oxygen in H2SO4used.

A .

1.5×1023, 0.75×1023, 3×1023

B .

0.75×1023, 0.75×1023, 6×1023

C .

6×1023, 1.5×1023, 3×1023

D .

1.5×1023, 1.5×1023, 6×1023

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ANSWER

The balanced equation for the reaction can be written as:

2NaOH+H2SO4→Na2

3.We know,

Molarity=Volume of solutionMoles

So,

0.15=25moles×1000

⟹moles=10000.15×25=3.75×10−3moles

We know,

1 moles→6.022×1023molecules

So, 3.75×10−3→6.022×1023×3.75×10−3molecules=2.258×1021 molecules

4.We know,

Molarity=Volume of solutionMoles

So,

0.15=25moles×1000

⟹moles=10000.15×25=3.75×10−3moles

We know,

1 moles→6.022×1023molecules

So, 3.75×10−3→6.022×1023×3.75×10−3molecules=2.258×1021 molecules

Explanation

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