1. Find the number of molecules present in 400 gram of NaOH ?
2. 400 gram of NaOH = ______ moles.
3. Mass of 1 molecule of NaOH.
4. Mass of 5 molecules of Na0H.
Please tell the answer you will get 63 points.
Answers
Answer:
Use the molecular formula to find the molar mass; to obtain the number of moles, divide the mass of compound by the molar mass of the compound expressed in grams.
Explanation:
Answer
1.The molecular weight of NaOH is 40 g/mol.
30 g of NaOH corresponds to 4030=0.75moles.
0.75 moles of NaOH contains 0.75 moles of Na.
The atomic mass of Na is 23 g/mol.
0.75 moles of Na corresponds to 23×0.75=17 g of Na.
2.What would you like to ask?
Chemistry
Some Basic Concepts of Chemistry
Stoichiometry and Stoichiometric Calculations
10g of NaOH required cert...
CHEMISTRY
Asked on December 30, 2019 byVanshika Sunil
10g of NaOH required certain amount of H2SO4 for complete neutralisation. Calculate the number of atoms of hydrogen, sulphur and oxygen in H2SO4used.
A .
1.5×1023, 0.75×1023, 3×1023
B .
0.75×1023, 0.75×1023, 6×1023
C .
6×1023, 1.5×1023, 3×1023
D .
1.5×1023, 1.5×1023, 6×1023
MEDIUM
Share
Save
ANSWER
The balanced equation for the reaction can be written as:
2NaOH+H2SO4→Na2
3.We know,
Molarity=Volume of solutionMoles
So,
0.15=25moles×1000
⟹moles=10000.15×25=3.75×10−3moles
We know,
1 moles→6.022×1023molecules
So, 3.75×10−3→6.022×1023×3.75×10−3molecules=2.258×1021 molecules
4.We know,
Molarity=Volume of solutionMoles
So,
0.15=25moles×1000
⟹moles=10000.15×25=3.75×10−3moles
We know,
1 moles→6.022×1023molecules
So, 3.75×10−3→6.022×1023×3.75×10−3molecules=2.258×1021 molecules
Explanation