Math, asked by rinkusah34, 11 months ago


1. Find the number of sides a polygon has if the sum of the measures of the interior angles is
(i). 50 right angles (ii) 1800°.
2. Is it possible to have a regular polygon if each interior angle is 110°?​

Answers

Answered by shobhafaujdar84
4

Answer:

Step-by-step explanation:

We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.

We also know that, the sum of the angles of a triangle = 180°.

Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)

= 2 right angles × (n – 2)

= 2(n – 2) right angles

= (2n – 4) right angles

Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.

Thus, each interior angle of the polygon = (2n – 4)/n right angles.

Answered by kanojiaujjwal13
3

Answer:

(1) 50 right angle-is 27 degree and (2) 1800degree - 12 degree

Step-by-step explanation:

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