Question

1) Find the number of sides of a regular polygon whose each interior angle is

135degrees
fast

Answer 1

[(n-2)×180°]/n =135°,


[(n-2)×4]=3n,


4n-8=3n,

then

4n-3n=8,

n=8 (Octagon)

Answer 2

The interior angles are 135°, so the exterior angles are 180° - 135° = 45°.

All the exterior angles add up to 360°, so if we divide 360° by 45° we find there are 8 exterior angles.

SO, ANSWER IS 8 SIDES