Question

1) find the number which when increased bye 30 % becomes 39
2) find the number which when decreased by 8% becomes 506 .

(who will give me right answer I will give him / her thanks, and follow him / her) ​

Answer 1

Answer:

1) $x\:=\:30$

2) $x\:=\:550$

Step-by-step explanation:

1) find the number which when increased bye 30 % becomes 39

Let the number be x

According to statement,

x + 30% of x = 39

x + $\frac{30}{100} \:x\:=\:39$

x + $\frac{100x\:+\:30x}{100}\:=\:39</h3><h3>[tex]\frac{130x}{100}\:=\:39$

$x\:=\:\frac{39\:×\:100}{130}\:=\:30$

____________________

2) find the number which when decreased by 8% becomes 506 .

Let the number be x

Decrease = 8% of x

$=\:\frac{8}{100}x\:=\:\frac{2}{25}x$

According to statement,

$x\: - \:\frac{2}{25}x\:=\:506$

$\frac{25x\: - \:2x}{25}\:=\:506$

$\frac{23}{25}x\:=\:506$

$\:=\:\frac{560×25}{23}\:=\:\frac{12650}{23}$

$=\:550$

Therefore, the number is 550

Answer 2

Mark to the answer as brainliest ⬆️

Answer:

1) $\:x=30$

2) $x\:=550$