Question

1. Find the perimeter of a rectangle in which:
length= 8m 5dm and breadth= 6m and 8dm​

Answer 1

Answer :-

• The perimeter of rectangle is 306dm.

Step-by-step explanation:

To Find :-

• The perimeter of rectangle

Solution:

Given that,

• The length of rectangle = 8m 5dm
• The breadth of rectangle = 6m 8dm

Firstly, converting length and breadth of rectangle to dm from m.

Length :-

=> ( 8m = 80dm ) + 5dm

=> 80dm + 5dm

=> 85dm

Breadth :-

=> ( 6m = 60dm ) + 8dm

=> 60dm + 8dm

=> 68dm

Now, According the question,

• The perimeter of rectangle

As we know that,

Perimeter of rectangle = 2 ( l + b ),

Where,

• l = Length
• b = Breadth

Therefore,

=> Perimeter = 2 ( Length + Breadth )

=> 2 ( 85 + 68 )

=> 2 ( 153 )

=> 2*153

=> 306dm.

Hence,

• The perimeter of rectangle is 306dm.

Answer 2

$\huge\bold\red{Question}$

• Find the perimeter of a rectangle in which:
• length= 8m 5dm and breadth= 6m and 8dm

$\huge\bold\red{Solution}$

$\huge\rm\purple{Formula-}$

Perimeter of a rectangle=

• 2(Length+Breadth)
• 2(L+B)

Now based on the formula above we will calculate the perimeter by the given length and breadth.

• $\implies$2 (8 m 5 Dm +6m 8 dm)

Convert m (meter) to dm (deca meter)

1 m=10 dm

:.8m=8×10 dm

=>80 dm

6 m=6×10 dm

=>60 dm

• $\implies$2 (85 dm + 68 dm)
• $\implies$2×153 dm
• $\implies$Perimeter=306 dm