Question

1. Find the perimeter of a triangle whose sides are 3 cm, 4 cm and 5 cm?

2. Find the side of a square whose perimeter is 40 m?

3. Find the cost of fencing a square of park of side 200 m at the rate of 20 rupees per meter.

​

Answer 1

Perimeter of a triangle is sum of all sides
So 3+4+5=12
Perimeter of a square =4xS
So let the side be x
4xX=40 so x=40/4=10
Aa given above perimeter is 4xS
So 4x200=800
Now 800x20=16000

Answer 2

Answer:

Step-by-step explanation:

1. Perimeter of triangle = Sum of 3 sides

                                       =(3+4+5)cm

                                       = 12 cm

2. Perimeter of square = 4*Side

                          40m     = 4 * s

                         40m/4  = Side

                            Side   = 10m  

3.Perimeter of square = 4*Side

                                       = 4*200m

                                       = 800m

Cost of Fencing at rate of 20 rupees per meter

                                       =(800*20)rupees

                                       = 16000 Rupees

Therefore, Ans of -:

1. 12 cm

2. 10m

3. 16000 Rupees

Hope it helps u