Question

1. Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.​

Answer 1

Answer:

perimeter of a triangle is equal to sum of all the sides

there fore 10 + 14 + 15=39

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Answer 2

• The perimeter of the triangle = 39 cm.

Given :

The three sides of the triangle :

• The first side = 10 cm.
• The second side = 14 cm.
• The third side = 15 cm.

To Find :

• The perimeter of the triangle.

Solution :

We know that,

The perimeter of the triangle = a + b + c

Where,

• The first side is denoted by a.
• The second side is denoted by b.
• The third side is denoted by c.

Given,

• a = 10 cm.
• b = 14 cm.
• c = 15 cm.

Now, substitute all the values in the formula of the perimeter of the triangle.

$: \implies \bf{10 \: cm + 14 \: cm + 15 \: cm} \\ \\ \\ : \implies \bf{24 \: cm + 15 \: cm} \\ \\ \\ : \implies \bf{39 \: cm} \\ \\ \\ \: \: \: \bf \therefore \: \: perimeter = 39 \: cm$

Hence,

The perimeter of the triangle is 39 cm.

__________________________

Additional Information :

Some formulas of the triangle :-

1) Area of the triangle = 1/2 × b × h

Where,

• b = base.
• h = height.

2) Perimeter of the triangle = a + b + c

Where,

• a = first side.
• b = second side.
• c = third side.

3) Base of the triangle when area is given,

→ 2 ( A / h )

Where,

• A = area of the triangle.
• h = height.

4) First side of the triangle when perimeter is given,

→ a = P – b – c

Where,

• a = first side.
• b = second side.
• c = third side.
• P = perimeter.

5) Second side of the triangle when perimeter is given,

→ b = P – a – c

Where,

• a = first side.
• b = second side.
• c = third side.
• P = perimeter.

6) Third side of the triangle when perimeter is given,

→ c = P – b – c

Where,

• a = first side.
• b = second side.
• c = third side.
• P = perimeter.

7) Height of the triangle = 2 ( A / b )

Where,

• A = area of the triangle.
• b = base.