Math, asked by ItzBrainlyQuestioner, 1 month ago

1. Find the Perimeter of the rectangle whose :
i) Length = 3m
Breadth = 2m
ii) Length = 50m
Breadth = 25m
iii) Length = 150 cm
Breadth = 1 cm
iv) Length = 240 m
Breadth = 180 m

2. A farmer has a rectangular field of length and breadth 240 m and 180 m resp. He wants to fence it with 3 rounds of rope. What is the total length of rope he must use?

3. Find the distance travelled by Ajay if he takes 3 rounds of square park of side 70 m.

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Answers

Answered by IIRenuII
14

 \bold\green{♧  \:  \: Question  \: 1 :}

  • Find the perimeter of the rectangle whose :
  1. Length = 3m & Breadth = 2m
  2. Length = 50m & Breadth = 25m
  3. Length = 150cm & Breadth = 1cm
  4. Length = 240m & Breadth = 180m

 \bold\green{♧  \:  \: Answer \:  1 :}

  \bold\red{◇  \: Perimeter \:  of \:  Rectangle = 2×(l + b)}

1. Given,

  • Length = 3 m
  • Breadth = 2 m

To Find,

  • Perimeter?

Solution,

Perimeter = 2 × (l + b)

Perimeter = [2 × (3 + 2)] m

Perimeter = (2 × 5) m

Perimeter = 10 m

2. Given,

  • Length = 50 m
  • Breadth = 25 m

To Find,

  • Perimeter?

Solution,

Perimeter = [2 × (50 + 25)] m

Perimeter = (2 × 75) m

Perimeter = 150 m

3. Given,

  • Length = 150 cm
  • Breadth = 1 cm

To Find,

  • Perimeter?

Solution,

Perimeter = [2 × (150 + 1)] cm

Perimeter = (2 × 151) cm

Perimeter = 302 cm

4. Given,

  • Length = 240 m
  • Breadth = 180 m

To Find,

  • Perimeter?

Solution,

Perimeter = [2 × (240 + 180)] m

Perimeter = (2 × 420) m

Perimeter = 840 m

 \bold\green{♧  \:  \: Question  \: 2 :}

  • A farmer has a rectangular field of length and breadth 240 m & 180 m respectively. He wants to fence it with 3 rounds of rope. What is the total length of rope he must use?

 \bold\green{♧  \:  \: Answer \:  2 :}

  • The farmer wants to fence his field with 3 rounds of rope. So, he has to cover three times the perimeter of that field.

First we calculate, the perimeter of the field.

Perimeter of field = 2 × (l + b)

Perimeter = [2 × (240 + 180)] m

Perimeter = (2 × 420) m

Perimeter = 840 m

Total length of rope required = 3 × Perimeter of the field

3 × 840 m

2520 m

 \bold\green{♧ \:  \:  Question  \: 3 :}

  • Find the distance travelled by Ajay if he takes three rounds of square park of side 70 m.

 \bold\green{♧  \:  \: Answer \:  3 :}

Distance travelled by Ajay to take three rounds of square park = 3 × Perimeter of square.

 \bold\red{Perimeter \:  of \:  square = 4 × side}

Distance travelled by Ajay = [ 3 × ( Perimeter of square)

[ 3 × (4 × 70) ] m

(3 × 280) m

840 m

Answered by MoodyCloud
28

Answer:

1. (i) 10 m.

(ii) 150 m.

(iii) 302 cm.

(iv) 840 m.

2. Total length of rope he must use is 2520 m.

3. Distance travelled by Ajay is 840 m.

Step-by-step explanation:

We know,

Perimeter of rectangle = 2×(length + breadth)

➊ i) Length = 3m, Breadth = 2m

 \longrightarrow Perimeter = 2 × (3 + 2)

 \longrightarrow Perimeter = 6 + 4

 \longrightarrow Perimeter = 10

Thus,

Perimeter of rectangle is 10 m.

ii) Length = 50m, Breadth = 25m

 \longrightarrow Perimeter = 2 × (50 + 25)

 \longrightarrow Perimeter = 100 + 50

 \longrightarrow Perimeter = 150

Thus,

Perimeter of rectangle is 150 m.

iii) Length = 150 cm, Breadth = 1 cm

 \longrightarrow Perimeter = 2 × (150 + 1)

 \longrightarrow Perimeter = 300 + 2

 \longrightarrow Perimeter = 302

Thus,

Perimeter of rectangle is 302 cm.

iv) Length = 240 m, Breadth = 180 m

 \longrightarrow Perimeter = 2 × (240 + 180)

 \longrightarrow Perimeter = 480 + 360

 \longrightarrow Perimeter = 840

Thus,

Perimeter of rectangle is 840 m.

➋ Given,

  • Length is 240 m.
  • Breadth is 180 m.

We need to find fence.

We know,

Fence = Perimeter

So,

 \longrightarrow Fence = 2 × (240 + 180)

 \longrightarrow Fence = 480 + 360

 \longrightarrow Fence = 840.

He fence it 3 times (or 3 rounds).

So, Total length of rope = 3 × 840

 \longrightarrow 2520

Thus,

Total length of rope he must use is 2520 m.

➌ Side of square park is 70 m.

He takes 3 rounds of park then,

 \longrightarrow Total distance travelled by Ajay = Perimeter of square park × 3

 \longrightarrow Total distance = (4 × 70) × 3

 \longrightarrow Total distance = 840

Thus,

Total distance travelled by Ajay is 840 m.

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