1. Find the Perimeter of the rectangle whose :
i) Length = 3m
Breadth = 2m
ii) Length = 50m
Breadth = 25m
iii) Length = 150 cm
Breadth = 1 cm
iv) Length = 240 m
Breadth = 180 m
2. A farmer has a rectangular field of length and breadth 240 m and 180 m resp. He wants to fence it with 3 rounds of rope. What is the total length of rope he must use?
3. Find the distance travelled by Ajay if he takes 3 rounds of square park of side 70 m.
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Answers
- Find the perimeter of the rectangle whose :
- Length = 3m & Breadth = 2m
- Length = 50m & Breadth = 25m
- Length = 150cm & Breadth = 1cm
- Length = 240m & Breadth = 180m
1. Given,
- Length = 3 m
- Breadth = 2 m
To Find,
- Perimeter?
Solution,
Perimeter = 2 × (l + b)
⟹ Perimeter = [2 × (3 + 2)] m
⟹ Perimeter = (2 × 5) m
⟹ Perimeter = 10 m
2. Given,
- Length = 50 m
- Breadth = 25 m
To Find,
- Perimeter?
Solution,
⟹ Perimeter = [2 × (50 + 25)] m
⟹ Perimeter = (2 × 75) m
⟹ Perimeter = 150 m
3. Given,
- Length = 150 cm
- Breadth = 1 cm
To Find,
- Perimeter?
Solution,
⟹ Perimeter = [2 × (150 + 1)] cm
⟹ Perimeter = (2 × 151) cm
⟹ Perimeter = 302 cm
4. Given,
- Length = 240 m
- Breadth = 180 m
To Find,
- Perimeter?
Solution,
⟹ Perimeter = [2 × (240 + 180)] m
⟹ Perimeter = (2 × 420) m
⟹ Perimeter = 840 m
- A farmer has a rectangular field of length and breadth 240 m & 180 m respectively. He wants to fence it with 3 rounds of rope. What is the total length of rope he must use?
- The farmer wants to fence his field with 3 rounds of rope. So, he has to cover three times the perimeter of that field.
First we calculate, the perimeter of the field.
Perimeter of field = 2 × (l + b)
⟹ Perimeter = [2 × (240 + 180)] m
⟹ Perimeter = (2 × 420) m
⟹ Perimeter = 840 m
Total length of rope required = 3 × Perimeter of the field
⟹ 3 × 840 m
⟹ 2520 m
- Find the distance travelled by Ajay if he takes three rounds of square park of side 70 m.
Distance travelled by Ajay to take three rounds of square park = 3 × Perimeter of square.
Distance travelled by Ajay = [ 3 × ( Perimeter of square)
⟹ [ 3 × (4 × 70) ] m
⟹ (3 × 280) m
⟹ 840 m
Answer:
1. (i) 10 m.
(ii) 150 m.
(iii) 302 cm.
(iv) 840 m.
2. Total length of rope he must use is 2520 m.
3. Distance travelled by Ajay is 840 m.
Step-by-step explanation:
We know,
• Perimeter of rectangle = 2×(length + breadth)
➊ i) Length = 3m, Breadth = 2m
Perimeter = 2 × (3 + 2)
Perimeter = 6 + 4
Perimeter = 10
Thus,
Perimeter of rectangle is 10 m.
ii) Length = 50m, Breadth = 25m
Perimeter = 2 × (50 + 25)
Perimeter = 100 + 50
Perimeter = 150
Thus,
Perimeter of rectangle is 150 m.
iii) Length = 150 cm, Breadth = 1 cm
Perimeter = 2 × (150 + 1)
Perimeter = 300 + 2
Perimeter = 302
Thus,
Perimeter of rectangle is 302 cm.
iv) Length = 240 m, Breadth = 180 m
Perimeter = 2 × (240 + 180)
Perimeter = 480 + 360
Perimeter = 840
Thus,
Perimeter of rectangle is 840 m.
➋ Given,
- Length is 240 m.
- Breadth is 180 m.
We need to find fence.
We know,
Fence = Perimeter
So,
Fence = 2 × (240 + 180)
Fence = 480 + 360
Fence = 840.
He fence it 3 times (or 3 rounds).
So, Total length of rope = 3 × 840
2520
Thus,
Total length of rope he must use is 2520 m.
➌ Side of square park is 70 m.
He takes 3 rounds of park then,
Total distance travelled by Ajay = Perimeter of square park × 3
Total distance = (4 × 70) × 3
Total distance = 840
Thus,
Total distance travelled by Ajay is 840 m.