Question

1.
Find the point of intersection of the lines 4x + 8y -1 = 0, 2x - 8y +1 = 0.​

Answer 1

Answer:

the point of intersection is (0,1/8)

Step-by-step explanation:

by elimination process,

4x+8y-1=0

2x-8y+1=0

we get , x=0

substitute x=0 in 4x+8y-1=0

4(0)+8y-1=0

8y-1=0

y=1/8

Answer 2

Therefore the point of intersection of the given 2 lines 4x + 8y -1 = 0 and 2x - 8y +1 = 0 is ( 0, 1/8 ).

Given:

The equation of lines are 4x + 8y -1 = 0 and 2x - 8y +1 = 0.​

To Find:

The value of the point of intersection of the given lines 4x + 8y -1 = 0 and 2x - 8y +1 = 0.​

Solution:

The given question can be solved as shown below.

The given equations of lines can be written as shown below.

⇒ 4x + 8y -1 = 0 ⇒ 4x + 8y = 1          (i.)

⇒ 2x - 8y +1 = 0 ⇒ 2x - 8y = -1           (ii.)

The 2 equations can be solved using the 'Elimination Method'.

Multiplying the equation-(ii.) by '2',

So we get, 4x + 16y = -2

Now solving both equations using the Elimination Method.

4x + 8y = 1

4x - 16y = -2

(-)   (-)       (-)  

0  + 24y = 3     ⇒ y = 3/24 = 1/8

Hence the value of y is 1/8.

Now substitute y = 1/8 in equation-(i.),

⇒ 4x + 8y = 1

⇒ 4x + 8 ( 1/8 ) = 1

⇒ 4x + 1 = 1

⇒ 4x = 0 ⇒ x = 0

Hence the value of x is 1.

Therefore the point of intersection of the given 2 lines 4x + 8y -1 = 0 and 2x - 8y +1 = 0 is ( 0, 1/8 ).

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