Question

1. Find the positive root of 3x? +6 = 9.​

Answer 1

Answer:please mark me brainliest

Hi ,

Sqrt ( 3x^2 + 6 ) = 9

Do the square bothsides of the

Equation.

3x^2 + 6 = 81

3x^2 = 81 - 6

3x^2 = 75

Divide bothsides with 3

3x^2 / 3 = 75/ 3

x^2 = 25

Now ,

x = sqrt ( 25 )

x = + or - 5

But we need pisitive root ,

therefore ,

x = 5

I hope this helps you.

****

Answer 2

3x  

2

+6=81

3x  

2

=81−6

3x  

2

=75

x  

2

=  

3

75

​  

 

x  

2

=25

x=  

25

​  

 

x=±5

But positive root:

x=5