Question

1. Find the positive root of root3xsquare+6=9

Answer 1

$\sqrt{(3x)^2} +6=9$

Square root is separating a number into two equal groups.

$\sqrt{3x\times 3x} +6=9$

Since square root is positive value, x is positive.

$3x+ 6=9$

So, x is 1