Question

1.find the product of (a²bc²) ( 9ab²c²) (-4ab²c⁴) and verify the result for a=1/2 , b = -1, c=1.
2.find the area of a rectangle whose sides are 2a and 3a.​

Answer 1

Step-by-step explanation:

1.

$( {a}^{2} b {c}^{2} )(9a {b}^{2} {c}^{2} )( - 4a {b}^{2} {c}^{2}) \\ = - 36 {a}^{4} {b}^{5} {c}^{8}$

Result when a=1/2, b=-1,c=1

$- 36 {a}^{4} {b}^{5} {c}^{8} = - 36 \times {( \frac{1}{2} )}^{4} \times {( - 1)}^{5} \times {(1)}^{8} \\ = - 36 \times \frac{1}{16} \times ( - 1) \times 1 \\ = \frac{36}{16} = \frac{9}{4}$

2.

Length = 3a, width =2a

Area of Rectangle = length*width

$area \: = length \times width \\ = 3a \times 2a \\ = 6 {a}^{2}$