Math, asked by DIGIVIJA, 2 months ago

1.Find the ratio in which the line-segmentjoiningthepoints(-2,-2)and(3,7)isdividedinternally

bythey-axisl​

Answers

Answered by rishikaagarwal259
0

Answer:

2:3

Step-by-step explanation:

Using the section formula, if a

point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then (x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

Substituting (x

1

,y

1

)=(−2,−3) and (x

2

,y

2

)=(3,7) in the section formula, we get the point (

m+n

m(3)+n(−2)

,

m+n

m(7)+n(−3)

)=(

m+n

3m−2n

,

m+n

7m−3n

)

As the

point lies on y - axis, x -coordinate =0.

=>

m+n

3m−2n

=0

=>3m=2n or m:n=2:3

Similar questions