1) Find the ratio in which the point (4,8) divides the line segment joining the points (5,7) and (3,9)
Answers
Answered by
0
Answer:
Given point (8, 4) = C x , y
Let A(5,−2)B(9,6)
x
1
y
1
x
2
y
2
we have to find the
ratio of AC & CB
Let ratio = k : 1
m
1
:m
2
=k:1
using section formula
x=
m
1
+m
2
m
1
x
2
+m
2
x
1
8=
1+k
k(9)+1(5)
8=(1+k)=9k+5
9k+5−8−8k=0
k=3
The ratio is k:1
=3:1
Answered by
2
Answer:
1:1
Shortcut:
the ratio in which (x,y) divides (x1,y1) and (x2,y2) is x1-x:x-x2 and y1-y:y-y2
PLZ:
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Step-by-step explanation:
the ratio in which the point (4,8) divides the line segment joining the points (5,7) and (3,9) is 5-4:4-3=1:1
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