1. Find the ratio of 3 m to 1 km in its simplest form.
2. Find the value of x in:
100 : x : x : 81
3. 25 men can reap a field in 12 days. In how many days can 15 men reap the same field?
4. If 12,4,9 and x are in proportion, then find the value of x.
5. A poster is 1.5 m long and 75 cm wide. Find the ratio of the length and breadth of the poster in lowest term.
6. By selling a computer for 23,000, a dealer earns a profit of 15%. Find the CP of the computer.
Answers
Answer:
1) 1km = 1000m
3m : 1000m
2)100/x = x/81
100×81= x^2
x= square root of 100x81=10×9 =90
x=90
3)25 men ----- 12 days
15 men -----?(x)
25 .x = 12×15
x= 12x15/25
x= 12x 3/5
36/5 =x
x=7.2 days
4)12:4 in proportion with9:x
12/4 = 9/x
12x = 36
x= 36/12
x=3
6) SP= 23000 rs
p%=15
CP= ?
CP = SP x100/ 100+p%
= 23000 x100 / 100+ 15
= 23000x100/ 115
CP = 2000 rupees
5)length =1.5m
breadth = 75cm
1m =100cm
1.5m = 1.5x100= 150cm
ratio= 150cm : 75cm
= 10 : 5
=2:1
Answer:
1) 300m:1 km find ratio simplest ... 300m/1000please mark me as a brain list ... So, 1 km = 1000 m .
2) 25:81::36:x
25:81::36:x⇒5 ^2:9 ^2 :: 6 ^2 :x
2 :xTherefore, ⇒x=10 ^2
⇒x=100
3) 12*15 =7.2 days
4) x:4 = 9:12
By cross product rule
" product of extreme = product of means x × 12 =4×9
x = 4×9/12
x= 36/12
x = 3
5) Perimeter of rectangle = 100mratio of length is to breadth = 3:2 = 3x : 2xPerimeter = 2(l+b)P = 2(3x+2x)= 6x + 4x = 10x10x = 100 ; x = 100/10 = 10l = 3x = 3 × 10 = 30 mb = 2x = 2 × 10 = 20 mArea of rectangle = length × breadth ( l×b )A = 30 × 20 = 600 sq.m
6) answer is in the photo ok......
Step-by-step explanation:
Hope this helps you thanku ｡◕‿◕｡
