Question

1) Find the ratio of areas of two triangles whose base iscommon & height are 4 & 8 respectively.

Answer 1

Answer:

$1:2$

Step-by-step explanation:

Let the triangles be A and B respectively,

We know,

Area = $1/2 \times base \times height$

∴ Ratio = $\frac{Area_{a} }{Area_{b}}$

⇒$\frac{1/2 \times base \times height_{a} }{1/2 \times base \times height_{b} }$

⇒$\frac{height_{a} }{height_{b} }$                                       [ ∵ $1/2 \times base$ gets cancelled out]

⇒$\frac{4}{8}$

⇒1/2 = 1:2

∴ The Ratio is 1:2