Question

1. Find the ratio of heat produced in 3 ohm and 6 ohm.. 2. Pd across 4 ohm



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Answer 1

Answer:

Ratio of heat produced in 3Ω and 6Ω is 2 : 1

pd across 4Ω resistor = 33.3 V

Explanation:

3Ω || 6Ω

Equivalent resistance of parallel combination is

Rp = R₁ R₂/(R₁ + R₂) = 3 x6/9 = 2 Ω

1) The pd across 3Ω and 6Ω is same = V₃ (say)

Ratio of heat produced in 3Ω and 6Ω is

H = (V²/R)t

Since V is same

H ∝ 1/R

H₁/H₂ = R2/R1 = 6/3 = 2

Ratio of heat produced in 3Ω and 6Ω is 2 : 1

2) In series combination, potential devides in the ratio of resistances

4Ω and Rp =2Ω are in series

ratio is of resistances 2: 1

pd across 4Ω resistor = 2/3 x 50 = 100/3 = 33.3 V