Physics, asked by reddyvenkatanarayan, 5 months ago

1. Find the ratio of rates of spontaneous emission and
stimulated emission for a
tungsten filament lamp
operating at a temperatuse
a temperature of 2000k, taking se
average frequency to be5×10^14
Hz​

Answers

Answered by vaibhavsemwal
3

Answer:

Ratio = 1.6*10^5

Explanation:

The ratio of spontaneous emission to stimulated emission is given by,

R=\frac{r_{spontaneous}}{r_{stimulated}} = \frac{B_{21}N_2\rho}{A_{21}N_2}=\frac{B\rho (v)}{A}=\frac{\rho(v)c^3}{8\pi h v^3}

R=\frac{A}{B\rho(v)}

As, \rho(v)=\frac{A}{B}*\frac{1}{e^{\frac{hv}{kT}}-1}

Required ratio = R=e^\frac{hv}{kT}-1

R=exp[\frac{6.64*10^-34*5* 10^14  }{1.38*10^-23 *2000} ]=162753.8 = 1.6*10^5

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