Question

1. Find the remainder obtained on dividing p(x) = 2x 2 – 3x – 2 by x – 2.

Answer 1

If a polynomial p(x) is divided by (x-a) remainder is always p(a). Remainder =p(2)=2×(2²)-3×2-2=8-6-2=8-8=0; Hence (x-2) is factor of p(x). Please mark the answer as brainliest.

Answer 2

Answer:

Remainder = 3

Step-by-step explanation:

Given,

Dividend = 2x^2 - 3x - 2

Divisor = x - 2

On dividing we get,

x - 2) 2x^2 - 3x - 2 ( 2x + 3

2x^2 - 6x

- +

_______________

0 + 3x - 2

3x - 6

- +

________________

0 + 3

________________

Hence,

Quotient = 2x + 3

Remainder = 3