1. Find the remainder obtained on dividing p(x) = 2x 2 – 3x – 2 by x – 2.
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Answered by
3
If a polynomial p(x) is divided by (x-a) remainder is always p(a). Remainder =p(2)=2×(2²)-3×2-2=8-6-2=8-8=0; Hence (x-2) is factor of p(x). Please mark the answer as brainliest.
Answered by
9
Answer:
Remainder = 3
Step-by-step explanation:
Given,
Dividend = 2x^2 - 3x - 2
Divisor = x - 2
On dividing we get,
x - 2) 2x^2 - 3x - 2 ( 2x + 3
2x^2 - 6x
- +
_______________
0 + 3x - 2
3x - 6
- +
________________
0 + 3
________________
Hence,
Quotient = 2x + 3
Remainder = 3
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