1. Find the remainder when r' + 3r+ 3r+1 is divided by
(i) x+π
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Answer ⇲
➣By remainder theorem
↦ x+1= 0
↦ x=.−1
↦ p(x)=.x 3 +3x 2 −3x−1p(−1)
↦ = (−1) 3 +3(−1) 2−3(−1)−1
↦ = −1+3(1)+3−1
↦ = 6−2
➔ =4
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