Question

1. Find the remainder when x^3+3x^2+3x+1 is divided by the following
Linear polynomials: 5+2x

Answer 1

Answer:  reminder of p(-5/2)=−27/8  when x^3+3x^2+3x+1 is divided by 5+2x

Step-by-step explanation:

Given,

x^3+3x^2+3x+1

​Dividing x^3+3x^2+3x+1 by 5+2x

So, x^3+3x^2+3x+1 is dividend and 5+2x is divisor

Put 5+2x=0

Therefore, x=-5/2

Let p(x)=x^3+3x^2+3x+1

Putting x=-5/2

p(-5/2)=(-5/2)^3+3(-5/2)^2+3(-5/2)+1

=(-125/8)+(75/4)-(15/2)+1

=(-125+150-60+8)/8

=-27/8

Thus, reminder of p(-5/2)=−27/8