Question

1. Find the remainder when x + 3r? + 3x + 1 is divided by
(1) x-1/2





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Answer 1

Step-by-step explanation:

Apply remainder theorem

=>x – 1/2 =0

=> x =  1/2

Replace x by  1/2 we get

=>x3+3x2 + 3x + 1

=>(1/2)3 + 3(1/2)2 + 3(1/2) + 1

=> 1/8 + 3/4 + 3/2 + 1

Add the fraction taking LCM of denominator we get

=>(1 + 6 + 12 + 8)/8

=>27/8

Remainder is 27/8

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