Question

1. Find the remainder when x' + 3x+ 3x + 1 is divided by x+1


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Answer 1

Answer:

Step-by-step explanation:

x³-3x²+3x-1

x³-x²-2x²+2x+x-1

x²(x-1)-2x(x-1)+1(x-1)

(x-1)(x²-2x+1)

(x-1)(x²-x-x+1)

(x-1){x(x-1)-1(x-1)}

(x-1)(x-1)(x-1)

Remainder = 0

Answer 2

Answer:

By remainder theorem

x+1=0

x=−1

p(x)=x^3+3x^3-3x1p(-1)

= (-1) ^3+3(−1)^2-3(-1)−1

=−1+3(1)+3−1

=−1+3+3−1

=6−2

=4

Thus remainder is 4.

Answered

by

Swagy_Boy❤