Question

1.
Find the remainder when x2 + 3x2 + 3x + 1 is divides by
(i)x+1
(ii) x-1/2
(iii) x
(iv) x+π
(v) 5+ 2x
​

Answer 1

Answer:

By long division, Therefore, the remainder is `27/8" .

Step-by-step explanation:

this is a correct answer

Answer 2

Answer:

By remainder theorem

x+1=0

x = -1

p(x)= x³ + 3x²-3x - 1p(-1)

=(-1)³ + 3(−1)² - 3(−1) – 1

= -1+3(1)+3-1

= −1+3+3-1

= 6-2

= 4

Step-by-step explanation:

Thus 4 is remainder

all no are in the same way