Question

1. Find the remainder when x³ + 3x² + 3x + 1 is divided by x-1/2​

Answer 1

$\huge\color{cyan}\boxed{\colorbox{black}{ANSWER ❤}}$

BY REMAINDER THEOREM,

THE ZERO OF THE POLYNOMIAL (x - 1/2) is 1/2

$p(x) = {x}^{3} + {3x}^{2} + 3x + 1$

$p( \frac{1}{2} ) = {( \frac{1}{2}) }^{3} + 3 {( \frac{1}{2} )}^{2} + 3( \frac{1}{2} ) + 1$

$= \frac{1}{8} + \frac{3}{4} + \frac{3}{2} + 1$

$= \frac{1 + 6 + 12 + 8}{8}$

$= \frac{27}{8}$

SO THE REMAINDER WOULD BE 27/8