Question

1. Find the roots of the following quadratic equations by factorization

1. 2x^2-x+1/8

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

${2x}^{2} - x + \frac{1}{8} = 0$

Multiplying the whole equation by 8 we get:

$8( {2x}^{2} - x + \frac{1}{8} ) = 8(0) \\ \\ 16 {x}^{2} - 8x + 1 = 0$

Splitting the mid term we get:

$16 {x}^{2} - 4x - 4x + 1 = 0 \\ \\ 4x(4x - 1) - 1(4x - 1) = 0 \\ \\ (4x - 1)(4x - 1) = 0 \\ \\ 4x - 1 = 0 \: \: and \: \: 4x - 1 = 0 \\ \\ 4x = 1 \: \: and \: \: 4x = 1 \\ \\ \bf x = \frac{1}{4} and \: \frac{1}{4}$