Question

1. Find the SI on 1000 at 2% for 6 months.
2. Af what rate will a sum of money double itself in 20 years​

Answer 1

Answer:

1)

$si = \frac{p \times r \times t}{100}$

$= \frac{1000 \times 2 \times 6}{100}$

$= 120$

so the simple interest will be 120 and amount will be 1120

2)

$since \: si \: = \frac{p \times r \times t}{100}$

$therefore \: r = \frac{si \times 100}{p \times t}$

here, according to the question si will be 1000×2=2000

so ,

$r = \frac{2000 \times 100}{1000 \times 20}$

r = 10%

so a rate of 10% on interest will be needed.

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