Question

1. Find the sides of rhombus whose
diagonals
are 16cm and 12 cm​

Answer 1

Answer:

10 cm

Step-by-step explanation:

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Answer 2

$\huge{\bold{\underline{\red{Answer\:-\:}}}}$

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➤ $\large{\bold{\green{Considered\:-\:}}}$

➜ let the ABCD be the rhombus

➜ AC and BD bisect at point O

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➤ $\large{\bold{\green{Weknow}}}$

➜ AC = 16 cm , BD = 12 cm

➜ diagonals of the rhombus bisect at right angles.

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➤ $\large{\bold{\green{Solution-}}}$

➜ AO = $\large{\frac{16}{2}}$ = 8 cm

➜ BO = $\large{\frac{12}{2}}$

➜ In right angled ∆AOB ,

➜ by using Pythagorean theorem,

➜ AB ^ 2 = AO ^2 + BO ^2

➜ AB ^ 2 = 8^2 + 6^2

➜ AB ^2 = 64 + 36

➜ AB ^2 = 100

➜ AB = √100

➜ AB = 10 CM

$\large{\boxed{SIDE\:=\:10cm}}$

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