Math, asked by laibafahim2, 10 months ago

1. Find the simple inte
amount.
2. What sum of money will yield 2170.10 as simple interest in 2 years 3 months at 6%
per
annum?
3 Find the rate nf interest when 800 fetches 130 as simple interest in 2 veze​

Answers

Answered by shj0730718
0

Answer:

2.P=Rs170.10

T=2yaers3months

T=2+  

12 3

​=  

4

9

​  

years

S.I.=  

100

P×R×T S.I.=  

100

170.10×6×  4 9

​  

Rs22.9635

​  

The required sum of money is Rs22.9635

3.Solution v:

Principal ( p ) = Rs 800

Simple interest ( I ) = Rs 130

Time ( t ) = 2½ years = (5/2 ) years

Let the rate of interest = r %

*****************************************

We know that ,

I = ( ptr )/100

Or

r = ( 100 × I )/( pt )

*************************************

Now ,

r = ( 100 × 130 )/[ 800 × (5/2 ) ]

=> r = ( 100 × 130 )/ ( 400 × 5 )

After cancellation , we get

= 13/2

= 6.5 %

Therefore ,

Rate of interest = r = 6.5%

Or

r = 13/2 %

•••••

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