Question

1. Find the simple interest at the end of one year for the following:
(a) 400 at 5% interest per annum.​

Answer 1

Step-by-step explanation:

P=400,r=5,n=2,t=2

SI=

100

Ptr

=

100

400×5×2

=40

CI=A−P

A=P(1+

100

r

)

n

=400(1+

100

5

)

2

=400×

400

441

CI=441−400=41

∴CI−SI=41−40=1

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Answer 2

Answer:

Question :-

Find the simple interest at the end of one year for the following:

(a) 400 at 5% interest per annum.

Answer :-

• The simple interest is ₹20.

Given:-

• Principal = ₹400
• Rate = 5%
• Time = 1 year

To find :-

• Simple interest

Solution:-

$\boxed{ \large{simple \: interest = \frac{p \times r \times t}{100} }}$

$\implies \: simple \: interest = \frac{400 \times 5 \times 1}{100} \\ \\ \implies \: simple \: interest =4 \times5 \\ \\ \implies \: simple \: interest =20$

Hence,

The simple interest is ₹20.