Question

1. Find the simple interest for the following.
a. P = 4000 for 2 years at 8% p.a.
C. P= 19,200 for 11 months at 6.5% p.a.
e. P = 22,500 for 2.75 years at 8.12% p.a.
b. P=10,500 for 146 days at 8.75% p.a.
d. P= 1000 for 5 years at 4% p.a.
f. P = 5000 for 5 years at 5% p.a.​

Answer 1

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a) Given:-

• Principal = Rs.4000
• Time = 2 years
• Rate = 8%

To find:-

Simple Interest (SI)

Solution:-

$\sf{SI =\dfrac{P\times R\times T}{100}}$

= $\sf{SI = \dfrac{4000\times2\times8}{100}}$

= $\sf{SI = 640}$

Therefore SI = Rs.640.

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c) Given:-

• Principal = Rs.19200

• Time = 11 months = $\sf{\dfrac{11}{12}\:yrs}$

• Rate = 6.5%

To Find:-

Simple Interest (SI)

Solution:-

$\sf{SI = \dfrac{P\times R\times T}{100}}$

= $\sf{SI = \dfrac{19200\times6.5\times11}{100\times12}}$

= $\sf{SI = 104}$

Therefore SI = Rs.104

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e) Given:-

• Principal = Rs.22500
• Time = 2.75 years
• Rate = 8.12%

To Find:-

Simple Interest (SI)

Solution:-

$\sf{SI = \dfrac{P\times R\times T}{100}}$

= $\sf{SI = \dfrac{22500\times8.12\times2.75}{100}}$

= $\sf{SI = \dfrac{225\times812\times275}{100\times100}}$

= $\sf{SI = \dfrac{225\times203\times11}{100}}$

= $\sf{SI = \dfrac{50245}{100}}$

= $\sf{SI = 502.45}$

Therefore SI = Rs.502.45

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b) Given:-

• Principal = Rs.10500

• Time = 145 days = $\sf{\dfrac{145}{365}\:yrs}$

• Rate = 8.75%

To find:-

Simple Interest (SI)

Solution:-

$\sf{SI = \dfrac{P\times R\times T}{100}}$

= $\sf{SI = \dfrac{10500\times8.75\times145}{100\times365}}$

= $\sf{SI = \dfrac{105\times875\times145}{100\times365}}$

= $\sf{SI = 364.98\:\:\:[Approx]}$

Therefore SI = Rs.364.98 [Approx]

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d) Given:-

• Principal = Rs.1000
• Time = 5 years
• Rate = 4%

To Find:-

Simple Interest (SI)

Solution:-

$\sf{SI = \dfrac{P\times R\times T}{100}}$

= $\sf{SI = \dfrac{1000\times5\times4}{100}}$

= $\sf{SI = 200}$

Therefore SI = Rs.200

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f) Given:-

• Principal = Rs.5000
• Time = 5 years
• Rate = 5%

To Find:-

Simple Interest

Solution:-

$\sf{SI = \dfrac{P\times R\times T}{100}}$

= $\sf{SI = \dfrac{5000\times5\times5}{100}}$

= $\sf{SI = 1250}$

Therefore SI= Rs.1250

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Answer 2

Answer:

a) Given:-

Principal = Rs.4000

Time = 2 years

Rate = 8%

To find:-

Simple Interest (SI)

Solution:-

\sf{SI =\dfrac{P\times R\times T}{100}}SI=

100

P×R×T

= \sf{SI = \dfrac{4000\times2\times8}{100}}SI=

100

4000×2×8

= \sf{SI = 640}SI=640

Therefore SI = Rs.640.

______________________________________

c) Given:-

Principal = Rs.19200

Time = 11 months = \sf{\dfrac{11}{12}\:yrs}

12

11

yrs

Rate = 6.5%

To Find:-

Simple Interest (SI)

Solution:-

\sf{SI = \dfrac{P\times R\times T}{100}}SI=

100

P×R×T

= \sf{SI = \dfrac{19200\times6.5\times11}{100\times12}}SI=

100×12

19200×6.5×11

= \sf{SI = 104}SI=104

Therefore SI = Rs.104

______________________________________

e) Given:-

Principal = Rs.22500

Time = 2.75 years

Rate = 8.12%

To Find:-

Simple Interest (SI)

Solution:-

\sf{SI = \dfrac{P\times R\times T}{100}}SI=

100

P×R×T

= \sf{SI = \dfrac{22500\times8.12\times2.75}{100}}SI=

100

22500×8.12×2.75

= \sf{SI = \dfrac{225\times812\times275}{100\times100}}SI=

100×100

225×812×275

= \sf{SI = \dfrac{225\times203\times11}{100}}SI=

100

225×203×11

= \sf{SI = \dfrac{50245}{100}}SI=

100

50245

= \sf{SI = 502.45}SI=502.45

Therefore SI = Rs.502.45

______________________________________

b) Given:-

Principal = Rs.10500

Time = 145 days = \sf{\dfrac{145}{365}\:yrs}

365

145

yrs

Rate = 8.75%

To find:-

Simple Interest (SI)

Solution:-

\sf{SI = \dfrac{P\times R\times T}{100}}SI=

100

P×R×T

= \sf{SI = \dfrac{10500\times8.75\times145}{100\times365}}SI=

100×365

10500×8.75×145

= \sf{SI = \dfrac{105\times875\times145}{100\times365}}SI=

100×365

105×875×145

= \sf{SI = 364.98\:\:\:[Approx]}SI=364.98[Approx]

Therefore SI = Rs.364.98 [Approx]

______________________________________

d) Given:-

Principal = Rs.1000

Time = 5 years

Rate = 4%

To Find:-

Simple Interest (SI)

Solution:-

\sf{SI = \dfrac{P\times R\times T}{100}}SI=

100

P×R×T

= \sf{SI = \dfrac{1000\times5\times4}{100}}SI=

100

1000×5×4

= \sf{SI = 200}SI=200

Therefore SI = Rs.200

______________________________________

f) Given:-

Principal = Rs.5000

Time = 5 years

Rate = 5%

To Find:-

Simple Interest

Solution:-

\sf{SI = \dfrac{P\times R\times T}{100}}SI=

100

P×R×T

= \sf{SI = \dfrac{5000\times5\times5}{100}}SI=

100

5000×5×5

= \sf{SI = 1250}SI=1250

Therefore SI= Rs.1250

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