Question

1. Find the simple interest on:
(1) 350 for 2 years at 11% per annum
(1) #20000 for 4 years at 8 % per annum
(it) 3648 for 8 months at 16 % per annum.
Also find the amount in each case.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

1)SI=p*r*t/100

     =350*11*2/100

     =77

Amount=p(1+r/100)to the power n

            =350(1+11/100)2

            =350(1.11)2

            =350*1.11*1.11

          A =431.235

2)SI=p*r*t/100

      =20000*8*4/100

     =6400

  AMOUNT=p(1+r/100)to the power n

                  =20000(1+8/100)4

                  =20000(1.08)4

                  =20000*1.08*1.08*1.08*1.08

              A  =27209.779

3)SI=p*r*t/100

     =3648*16*8/100*12

     =56033.28