1. Find the slope of the straight line
(i) 3x+4y- 6 =0 (ii) y = 7x+ 6 (iii) 4x= 5y + 3.
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Solution:
i ) Compare 3x + 4y - 6 = 0 with
ax + by + c = 0 ,
a = 3 , b = 4 , c = -6
slope of the line ( m ) = -a/b
=> m = - 3/4
ii ) Compare y = 7x + 6 with
y = mx + c ,
slope ( m ) = 7
iii ) Given 4x = 5y + 3
=. 4x - 5y - 3 = 0 compare this with
ax + by + c = 0 ,
a = 4 , b = -5. ,c = -3
slope the line ( m ) = -a/b
=> m = 4/( - 5 ) = -4/5
••••
i ) Compare 3x + 4y - 6 = 0 with
ax + by + c = 0 ,
a = 3 , b = 4 , c = -6
slope of the line ( m ) = -a/b
=> m = - 3/4
ii ) Compare y = 7x + 6 with
y = mx + c ,
slope ( m ) = 7
iii ) Given 4x = 5y + 3
=. 4x - 5y - 3 = 0 compare this with
ax + by + c = 0 ,
a = 4 , b = -5. ,c = -3
slope the line ( m ) = -a/b
=> m = 4/( - 5 ) = -4/5
••••
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