Question

1. Find the smallest 3 - digit number which is exactly divisible by 4, 5 and 6.​

Answer 1

Step-by-step explanation:

We Have :-

$a \: 3 \: digit \: number$

Solution :-

$we \: have \: 4 \: and \: 5 \: and \: 6 \\ \\ \\ lcm \: of \: these \: numbers \: is \: 60 \\ \\ \\ taking \: multiples \: of \: 60 \\ \\ \\ 60 \times 1 = 60 \\ \\ \\ 60 \times 2 = 120 \\ \\ \\ 120 \: is \: the \: smallest \: 3 \: digit \: no$

Answer 2

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QUESTION :

1. Find the smallest 3 - digit number which is exactly divisible by 4, 5 and 6

SOLUTION :

The three numbers are 4, 5 and 6

The required smallest number should be a multiple of their LCM

=> We need to find the LCM of 4, 5 and 6

LCM =>

Taking 2, => 2, 5, 3

=> The LCM is 60.

Smallest 3 Digit Number :

To Multiply the LCM of the above numbers by a constant such that the Resultant is the Smallest 3 Digit Number which is exactly

divisible by 4, 5 and 6.

We can easily find this constant to be 2.

Hence the required 3 Digit number :

=> 60 × 2

=> 120

Hence the required number comes out to be 120.

Answer :

The smallest 3 - digit number which is exactly divisible by 4, 5 and 6 is 120