(1) Find the smallest 5-digit number that is divisible by 35.
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The smallest 5digit number=10000 The remainder when 10000 devided by 35=25 and 25+10 is 35 Therefore the smallest 5 digit number that is divisible by 35 = 10000+10 =10010. Therefore, the smallest 5 digit number that is divisible by 35 = 10000 + 10 = 10010
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10000 is divided by 35=25and 25+10=35 therefore the smallest five digit number that is divisible by 35=10000+10=10010 therefore the smallest 5 digit number that is divisible by 35=10000+10=10010
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