Question

1. Find the smallest natural number which when divided by 16, 24, and 40 leaves a
remainder 8 in each case.

Answer 1

Answer

First find the LCM of 16, 24 and 40  

The LCM will be 240  

( 8 × 2 × 3 × 5 = 240)  

We know that the Remainder is 8 in each case

Now, we will add 8 to the LCM

ANSWER -  240 + 8 = 248  

Therefore 248 is the smallest number which when divided by 16, 24 and 40 leaves the remainder, 8.  

Lets say 248 is divided to 16 will give 8 as remainder,

248 / 16    

R = 8

248 is divided to 24 will again give 8 as remainder,

248 / 24

R= 8

248 is divided to 40 will give 8 as remainder,

248 / 40

R= 8