Question

1) Find the smallest number that is divisible by first 10 natural numbers. 2) Find the least positive integer which on adding 1 is exactly divisible by 126 and 600 Please reply its very urgent

Answer 1

question.1..first 10 natural numbers:
                    1,2,3,4,5,6,7,8,9,10

                  L.C.M of these natural numbers:
                   factors= 2×2×2×3×3×5×7
                               =2520
 the smallest number is 2520.

question.2.
least integer= L.C.M of 126 and 200 
factors=2*2*2*3*3*5*5*7
           =12600
least positive integer= 12600-1
                                  =12599

Answer 2

Answer:

2520

Step-by-step explanation:

The smallest no. that is divisible by first 10 natural no. Is 2520