Question

1 Find the smallest number that must be added to 563279 so
that it is divisible by 8?
2) Find the smallest number that can be subtracted from 2549
so that it becomes divisible by 4?
3) Write the nearest number to 1240 which is divisible by 11?
18) Write the nearest number to 205 which is divisible by 4?
=
4) LCM X________=_______
) Every number is a factor of
5) Kaprekar's constant is
6) LCM and HCF of Twin prime numbers is
7) HCF of two Consecutive numbers is
8) HCF of Consecutive even numbers is
9) HCF of Consecutive odd numbers is​

Answer 1

Answer:

1) 7 should be added

2) 1 should be subtracted

3) 112

4) 51

5) LCM*HCF =product of those two numbers

6) LCM IS 10 AND HCF IS 1

7)always even

8) always odd

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Answer 2

Step-by-step explanation:

Smallest number? What do you mean by that?

Considering your question as What is the smallest number that must be added to 289279 so that it is divisible by 8,

The answer is -∞.,

But,

If you meant What is the smallest positive number that must be added to 289279 so that it is divisible by 8,

Then, to take out the answer,

Divide 289279 by 8 and note the remainder.

The remainder will be 7.

Now,

If you subtract 7 from the number 289279, and divide it by 8,the remainder will be 0,i.e., it will be divisible by 8.

But, we need the smallest positive number that should be added,

Now, you know that consecutive multiples of 8 have a difference of 8.

So, 289279–7+8 is divisible by 8

289279+1 is divisible by 8.

Or better,

Just check the last 3 digits.

If the last 3 digits of a number are divisible by 8, or are 000, then the number is divisible by 8.

So, 1 is the smallest positive integer that should be added to 289279 to make it divisible by 8.

Hope it helps.

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