Math, asked by prabhadibodo9101, 10 months ago

1. Find the smallest number which is exactly divisible by 8, 10 and 12.
2. Find the least number which when divided by 18, 24 and 32. leaves a remainder 7 in
each case.
3. There are four bells, which toll at intervals of 3, 7, 12 and 14 seconds
respectively. The four bells begin to toll at 12 o'clock. When will they
next toll together and how often will they do so in 14 minutes?​

Answers

Answered by TBNRAnirudh
0

Answer:

Step-by-step explanation:

(I)8=2*2*2

10=2*5

12=2*2*3

lcm is 120

(II)

18=3*3*2

24=2*2*2*3

32=2*2*2*2*2

lcm is 288

so no is 295

(III)3=3*1

7=1*7

12=2*2*3

14=2*7

lcm is 84 sec

they ring together every 1 min and 24 sec

they ring 10 times in the span of 14 mins

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