1. Find the smallest number which when added to 5 is divisible by 12, 14 and 18.
Answers
Answer:
Factors of
12 = 2x2x3
15 = 3x5
18 = 2x3x3
LCM = 2x2x3x3x5 = 180
10000/180 = 55.5
So take the next higher number, 56 and multiply 180 by it to get
180*56 = 10080.
The smallest 5-digit number divisible by 12, 15 and 18 is 10080. Answer.
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Step-by-step explanation:
Take LCM of 12, 15 and 18.
Factors are
12=2*2*3,
15=3*5,
18=2*3*3.
Their LCM=2*2*3*3*5
=180.
Because smallest 5 digits number is 10000.
Let us divide it by 180
then for a quotient 55 remainder is 100
if we add 80 to it then it will be completely divided by 180 with a quotient 56.
Therefore 180*56=10080
So smallest 5 digits number divisible by 12, 15, and 18
is 10080
The smallest five digit number which is divisible by 12, 18 and 21 is?
What is the smallest 5 digit number which is exactly divisible by 12, 16, and 20?
What is the smallest number divisible by 18, 15, and 14?
What is the least five-digit number which is exactly divisible by 12, 15, and 18?
What is the smallest 5-digit number which is divisible by 9, 15 and 18?
LCM (12, 15, 18) = 180.
Now, we are to find smallest five-digit multiple of 180.
Smallest five-digit number = 10000.
(10000 / 180) gives a dividend of 55 leaves a remainder of 100.
Therefore, we need to add (180 - 100) = 80 to 10000 in order to make the sum divisible by 180.
Therefore, the answer is (10000 + 80) = 10080.