1. Find the smallest number which when divided by 16, 24, 32 and 40
leaves remainder 3 in each case
Answers
Answered by
0
Answer:
all number added 3 and find HCF
Answered by
1
Answer:
Answer is 477
Step-by-step explanation:
To find the smallest number
we have to do
LCM of 16,24,32 and 40
=>480
Then we have subtract 3 from 480
After that we will get the smallest number which will divided by 16,24,32 and 40 leaves remainder 3 in each case
=>480 - 3 = 477
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