Question

1. Find the smallest number which when divided by 24, 36 and 40 gives a remainder 5 each time?​

Answer 1

Answer:

120 is the smallest number when we divide remains 5

Step-by-step explanation:

$24 \div x = 5 \\ 24 \times 5 = x$

$x = 120$

and then

$36 \div x = 5 \\ x = 36 \times 5$

$x = 180$

and then

$40 \div x = 5 \\ x = 40 \times 5$

$x = 200$

here the smallest number is 120