Question

1. Find the smallest number
which when divided
by 30, 40 and 60 leaves the remainder 7 in each case​

Answer 1

Answer:

127

Step-by-step explanation:

LCM of 30, 40, 60 is 120

Add 7 to 120

= 127

so the smallest number which when divided by 30, 40, and 60 and leaves remainder 7 is 127

verification:

127 / 30 -

quotient = 4 and remainder = 7

127 / 40 -

quotient = 3 and remainder = 7

127 / 60 -

quotient = 2 and remainder = 7

in all cases remainder is 7

so the smallest number which when divided by 30, 40, and 60 and leaves remainder 7 is 127