1. Find the solution of the following pairs of unean ka
9x-2y=31
and 6x+5y=8 by elimination method
Answers
Answer
x = 3
y = -2
Given
9x - 2y = 31
6x + 5y = 8
To Find
To solve these equations by elimination method
Solution
9x - 2y = 31
Multiply this eq. with 5 on both sides ,
⇒ 5 ( 9x - 2y ) = 5(31)
⇒ 45x - 10y = 155 ... (1)
6x + 5y = 8
Multiply this equation with 2 on both sides ,
⇒ 2 ( 6x + 5y ) = 2(8)
⇒ 12x + 10y = 16 ... (2)
Now , Solve (1) + (2) ,
⇒ ( 45x - 10y ) + ( 12x + 10y ) = 155 + 16
⇒ 57x = 171
⇒ x = 3
Sub. x value in (2) ,
⇒ 12(3) + 10y = 16
⇒ 36 + 10y = 16
⇒ 10y = - 20
⇒ y = - 2
Answer:
x = 3 and y = -2
Step-by-step explanation:
9x - 2y = 31 and 6x + 5y = 8
→ 9x - 2y = 31 (×5)
→ 45x - 10y = 155
→ 45x - 155 = 10y ............(1)
→ 6x + 5y = 8 (×2)
→ 12x + 10y = 16
→ 16 - 12x = 10 y ..............(2)
On comparing both we get,
→ 45x - 155 = 16 - 12x
→ 45x + 12x = 16 + 155
→ 57x = 171
→ x = 3
Substitute value of x in (1)
→ 45(3) - 155 = 10y
→ 135 - 155 = 10y
→ -20 = 10y
→ -2 = y
Hence, the value of x is 3 and y is -2.