1. Find the square root of the following
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HELLO DEAR,
121*X^8*Y^6 * 1/81*X⁴Y^8
(11*X⁴*Y³)²/(9*X²*Y⁴)²
now the square of given no. Is
(11*x⁴*y³)/(9*x²*y⁴)
I HOPE ITS HELP YOU DEAR,
THANKS
121*X^8*Y^6 * 1/81*X⁴Y^8
(11*X⁴*Y³)²/(9*X²*Y⁴)²
now the square of given no. Is
(11*x⁴*y³)/(9*x²*y⁴)
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
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Solution :
√[ 121 x^8 y^6 ÷ 81 x⁴ y^8]
= √{[( 11 )² ( x⁴)² ( y³ )²] ÷ [9²(x²)²(y⁴)²]}
= √ [( 11 x⁴y³ )² / ( 9x²y⁴ )² ]
= ( 11x⁴y³ )/( 9x²y⁴ )
••••
√[ 121 x^8 y^6 ÷ 81 x⁴ y^8]
= √{[( 11 )² ( x⁴)² ( y³ )²] ÷ [9²(x²)²(y⁴)²]}
= √ [( 11 x⁴y³ )² / ( 9x²y⁴ )² ]
= ( 11x⁴y³ )/( 9x²y⁴ )
••••
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