Question

1. Find the squares of the following:
(i). 2a + 1
(ii) 3b + 20​

Answer 1

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Answer 2

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For question 1.

$\sf {(2a + 1)}^{2}$

$\sf = {(2a)}^{2} + {(1)}^{2} + 2 \times 2a \times 1$

$\sf = 4 {a}^{2} + 4a + 1$

For question 2.

$\sf {(3b + 20)}^{2}$

$\sf = {(3b)}^{2} + {(20)}^{2} + 2 \times 3b \times 20$

$\sf = 9 {b}^{2} + 120b + 400$

Identity used:-

$\sf {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$