Question

1. Find the sum of 24 terms of the AP 1,3,5,7,..​

Answer 1

Answer:

here a=1 , d= 2 , n= 24

Sn = n/2 [2a (n - 1) d]

= 24/2 [2 * 1 ( 24 - 1) 2]

= 12 [ 2 (23) 2]

= 12 [ 2* 23 * 2]

= 12 * 92

Sn = 1104